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CSC 101 Assessment QUESTION
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CSC 101 ASSESSMENT SOLUTION
1) Given that X2=3DFF base 16, we can convert it to base 10 by multiplying each digit by the corresponding power of 16 and adding the results.
The digits in 3DFF are 3, D, F, and 1. Their place values in base 16 are 16^2, 16^1, 16^0, and 16^0, respectively.
Answer
X2 = (3 x 16^2) + (D x 16^1) + (F x 16^0) + (1 x 16^0)
= 576 + 216 + 15 + 1
= 808
2) given that nkechi just got married draw a flow chart that can display nnanna if a first born is male and kamsiyo if the second born is a female
ANSWER
Start
Is the firstborn male?
Yes → Print “Nnanna”
No → Go to step “Is the secondborn female?”
Is the secondborn female?
Yes → Print “Kamsiyo”
No → Print “No child yet”
End
3) Given two teams A and B draw a flow chart that will A as a winner if only ronaldo plays and play the position 7 else b is the inner if merci plays and plays 9
ANSWER
Start
Is Ronaldo playing?
Yes → Is Ronaldo playing in position 7?
Yes → Team A wins
No → Go to step “Is Messi playing?”
Is Messi playing?
Yes → Is Messi playing in position 9?
Yes → Team B wins
No → Team A wins
End
NO 4
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4) Given that the las two digits of your reg no is a number of binary and u = AS draw a true table of i) A & B given that B is equal to 00101001. ii) Find a or b. iii) find a or b and A
ANS
Given that the last two digits of your registration number is 04, which is equal to 00000100 in binary, we can construct the truth table for A & B as follows:
i)
A | B | A & B |
---|---|---|
0 | 0 | 0 |
0 | 1 | 0 |
1 | 0 | 0 |
1 | 1 | 1 |
As you can see, the output of A & B is 1 only when both A and B are 1. Otherwise, the output is 0. |
ii)
The truth table for A or B is as follows:
A | B | A or B |
---|---|---|
0 | 0 | 0 |
0 | 1 | 1 |
1 | 0 | 1 |
1 | 1 | 1 |
As you can see, the output of A or B is 1 when at least one of A and B is 1. Otherwise, the output is 0. |
iii)
The truth table for A or B and A is as follows:
A | B | A or B and A |
---|---|---|
0 | 0 | 0 |
0 | 1 | 1 |
1 | 0 | 1 |
1 | 1 | 1 |
As you can see, the output of A or B and A is always 1. This is because A or B is always 1 when at least one of A and B is 1, and A is always 1. |
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